In the game of cricket, two teams take turns to bat or bowl. While only some players bowl, all eleven team members take part in batting. The bowling team aims to dismiss batters, one at a time, and the batting team sends out a replacement, in predetermined order, for each dismissed player. The order in which the batters come out is referred to as the “lineup” of the team. How many possible lineups do you think there are? Is your guess a few dozen, a few hundred possible lineups? You’ll be surprised that the answer is in the millions!

Since I cannot list millions of lineups here, I will start with a simple example. We will see how many possible arrangements there are for 3 players and extrapolate from 3 to 11.
A cricket team of 3 players
The Australian men’s cricket team has been shrunk, for the purposes of this blog, to three players: Travis, Jake and Marnus.
Possible lineups starting with Travis:
Travis, Jake, Marnus
Travis, Marnus, Jake
Similarly, we have 2 lineups starting with Jake and another 2 starting with Marnus. This gives a total of 6 possible lineups for a team of 3 batters.
To bat at number 1, we have 3 options. For each of these, we have 2 options remaining for the number 2 spot. Then, there is 1 option left to go in the number 3 spot. Below is an illustration of this.

We will read the “tree diagram” above from left to right, starting at the top. As can be seen, there are 3 possibilities for the first place, each corresponding to 2 more possibilities for the second spot. Only one possibility is left, each time, for the final spot.
Batting lineup for 11 players
Getting back to 11 players, the number of possible lineups will be
This is a number just short of 40 million possible lineups! The next time you are mad at the selection committee of a cricketing nation, take that into account.
Do you have any other examples of mathematical questions where the answer defies most people’s intuition? I would love for you to leave it in the comments.

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